C Language Storage Classes - Practice Questions 2026

Core Concepts: Here, we dive into the specific behavior of memory allocation. You will be tested on where variables are stored (Stack vs. Data Segment) and the initial default values (garbage values vs. zero) associated with different storage types.

Intermediate Concepts: This module explores the nuances of internal and external linkage. You will solve problems involving the static keyword in multi-file programs and how it limits the visibility of functions and variables to a single translation unit.

Advanced Concepts: Challenge yourself with complex pointer interactions, the volatile qualifier in conjunction with storage classes, and the behavior of register variables when dealing with address-of operators.

Real-world Scenarios: These questions simulate actual debugging tasks. You will analyze code snippets to find memory leaks or logical errors caused by incorrect storage class usage in high-performance computing environments.

Mixed Revision / Final Test: A comprehensive cumulative exam that pulls from all previous sections. This timed environment prepares you for the pressure of technical certification exams and competitive programming interviews.

Option 2: 6 6

Option 3: 6 7

Option 4: 5 6

Option 5: Compilation Error

Correct Answer: Option 3

Correct Answer Explanation: The variable x is declared as static. Static variables are initialized only once and retain their value between function calls. In the first call, x starts at 5, increments to 6, and prints 6. In the second call, x remains 6 from the previous execution, increments to 7, and prints 7.

Wrong Answers Explanation:

Option 2: Wrong because it assumes x is re-initialized to 5 every time the function is called, which is behavior typical of auto variables, not static.

Option 4: Wrong because the increment happens before the first print statement, so 5 cannot be the first output.

Option 5: Wrong because the syntax is perfectly valid C code.

Option 2: Register variables are always stored in the CPU cache.

Option 3: The compiler must store the variable in a CPU register if the keyword is used.

Option 4: You cannot use the & operator on a variable declared with the register keyword.

Option 5: Register variables have a global scope by default.

Correct Answer: Option 4

Correct Answer Explanation: In C, variables declared with the register storage class may be stored in CPU registers. Because registers do not have memory addresses, the C standard prohibits the use of the address-of operator (&) on these variables, even if the compiler decides to store them in RAM.

Wrong Answers Explanation:

Option 2: Wrong because "register" refers to CPU registers, not the cache, though the compiler makes the final decision.

Option 3: Wrong because the register keyword is only a hint to the compiler; the compiler can ignore it if no registers are available.

Option 4: Wrong because register variables are local to the block in which they are defined, not global.

This is a huge original question bank

You get support from instructors if you have questions

Each question has a detailed explanation

Mobile-compatible with the Udemy app

30-days money-back guarantee if you are not satisfied